What is the domain of f(x)=\sqrt[4]{x^2-8x} ?

The domain of f(x)=\sqrt[4]{x^2-8x} is x = 8

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domain of f(x)=\sqrt[4]{x^2-8x}

domain

x \leq 0 or x \geq 8

Interval Notation

(- \infty, 0] \cup [8, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 8

The function domain

x \leq 0 or x \geq 8

f (x) = x^{3} - 7

f (x) = 16 x - 4 x^{2}

2 x - 3 y - 12 = 0

\frac{4 x - 1}{5 - x}

8 x - y = - 16, (0, 0)

What is the domain of f(x)=\sqrt[4]{x^2-8x} ?
The domain of f(x)=\sqrt[4]{x^2-8x} is x<= 0\lor x>= 8