What is the range of f(x)=\sqrt[3]{x} ?

The range of f(x)=\sqrt[3]{x} is -infinity <f(x)<infinity

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range of f(x)=\sqrt[3]{x}

range

- \infty < f (x) < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

Inverse of

x^{3}

Find the domain of each inverse function

Domain of

x^{3} : - \infty < x < \infty

Combine the intervals

- \infty < f (x) < \infty

f (x) = \frac{( x + 5 )}{( x ^{2} + 3 x - 10 )}

f (x) = \frac{2 x - 3}{x ^{2} - 5 x + 6}

f (x) = \frac{1}{x + 11}

x - 4

f (x) = y

What is the range of f(x)=\sqrt[3]{x} ?
The range of f(x)=\sqrt[3]{x} is -infinity <f(x)<infinity