What is the asymptotes of f(x)=((x^2-4x))/(x^2-16) ?

The asymptotes of f(x)=((x^2-4x))/(x^2-16) is Vertical: x=-4,Horizontal: y=1

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asymptotes of f(x)=((x^2-4x))/(x^2-16)

asymptotes

f (x) = \frac{( x ^{2} - 4 x )}{x ^{2} - 16}

Vertical : x = - 4, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 4 x}{x ^{2} - 16} : x = - 4

Horizontal Asymptotes of

\frac{x ^{2} - 4 x}{x ^{2} - 16} : y = 1

Slant Asymptotes of

\frac{x ^{2} - 4 x}{x ^{2} - 16} :

None

Vertical : x = - 4, Horizontal : y = 1

x^{4} + 2

\frac{2 x ^{2} - 10}{x + 2}

15 + 5 sin (- \frac{π}{12} x + \frac{7 π}{4})

2 - 4 x^{3}

x - y = 1, (- 5, 5)

What is the asymptotes of f(x)=((x^2-4x))/(x^2-16) ?
The asymptotes of f(x)=((x^2-4x))/(x^2-16) is Vertical: x=-4,Horizontal: y=1