What is the extreme f(x)=4x^3-48x-7 ?

The extreme f(x)=4x^3-48x-7 is Maximum(-2,57),Minimum(2,-71)

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extreme f(x)=4x^3-48x-7

extreme points

f (x) = 4 x^{3} - 48 x - 7

Maximum (- 2, 57), Minimum (2, - 71)

Solution steps

f^{'} (x) = 12 x^{2} - 48

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

4 x^{3} - 48 x - 7 : 57

Maximum (- 2, 57)

Plug

x = 2

into

4 x^{3} - 48 x - 7 : - 71

Minimum (2, - 71)

Maximum (- 2, 57), Minimum (2, - 71)

f (x) = (x - 2)^{2} (x - 1)

y = \frac{x}{x ^{2} + 4}

0.001 x^{3} + 7 x + 54

y = 5 - 2 x

\frac{3 x}{x + 4}

What is the extreme f(x)=4x^3-48x-7 ?
The extreme f(x)=4x^3-48x-7 is Maximum(-2,57),Minimum(2,-71)