What is the inverse of f(x)=3(x+1)^2-15 ?

The inverse of f(x)=3(x+1)^2-15 is sqrt((x+15)/3)-1,-sqrt((x+15)/3)-1

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inverse of f(x)=3(x+1)^2-15

inverse

f (x) = 3 (x + 1)^{2} - 15

\frac{x + 15}{3} - 1, - \frac{x + 15}{3} - 1

Solution steps

y = 3 (x + 1)^{2} - 15

Replace

x

with

y

x = 3 (y + 1)^{2} - 15

Solve for

y, x = 3 (y + 1)^{2} - 15

\frac{x + 15}{3} - 1, - \frac{x + 15}{3} - 1

\frac{6 x}{x + 7}

f (x) = x^{2} - 3 x + 2

f (x) = 4 arccot (\frac{3 x}{4} - \frac{2}{3})

- sin (x)

f (x) = 2 tan (4 x)

What is the inverse of f(x)=3(x+1)^2-15 ?
The inverse of f(x)=3(x+1)^2-15 is sqrt((x+15)/3)-1,-sqrt((x+15)/3)-1