What is the range of f(x)=sqrt(x-9) ?

The range of f(x)=sqrt(x-9) is f(x)>= 0

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range of f(x)=sqrt(x-9)

range

f (x) = x - 9

f (x) \geq 0

Interval Notation

[0, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 0

f (x) \geq 0

f (x) = \frac{1}{x} + 3

(1, 2), (- 3, - 2)

y = 3 x + 7

f (x) = 1 - x

f (x) = \frac{x}{x ^{2} + 36}