What is the domain of ((x-8))/((x-1)(x+2)) ?

The domain of ((x-8))/((x-1)(x+2)) is x 1

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domain of ((x-8))/((x-1)(x+2))

domain

\frac{( x - 8 )}{( x - 1 ) ( x + 2 )}

x < - 2 or - 2 < x < 1 or x > 1

Solution steps

Find undefined (singularity) points:

x = 1, x = - 2

The function domain

x < - 2 or - 2 < x < 1 or x > 1

2 x^{3} - 7 x^{2} + 2 x + 3

f (x) = 2 x - 4 + 8

x^{2} + 2 x - 8

f (x) = 2 x^{7} - 9

y = 6 x - 5

What is the domain of ((x-8))/((x-1)(x+2)) ?
The domain of ((x-8))/((x-1)(x+2)) is x<-2\lor-2<x<1\lor x>1