What is the inverse of f(x)=3x^2-8 ?

The inverse of f(x)=3x^2-8 is sqrt((x+8)/3),-sqrt((x+8)/3)

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inverse of f(x)=3x^2-8

inverse

f (x) = 3 x^{2} - 8

\frac{x + 8}{3}, - \frac{x + 8}{3}

Solution steps

y = 3 x^{2} - 8

Replace

x

with

y

x = 3 y^{2} - 8

Solve for

y, x = 3 y^{2} - 8

\frac{x + 8}{3}, - \frac{x + 8}{3}

f (x) = \frac{3 x + 4}{- 5 x - 7}

f (x) = \frac{x}{x - 4}

(x + 3)^{2} - 1

f (x) = - 5 x^{3} + 15 x + 7

y = \frac{1}{3} x + 1

What is the inverse of f(x)=3x^2-8 ?
The inverse of f(x)=3x^2-8 is sqrt((x+8)/3),-sqrt((x+8)/3)