What is the extreme f(x)=2x^3-3x^2-432x ?

The extreme f(x)=2x^3-3x^2-432x is Maximum(-8,2240),Minimum(9,-2673)

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extreme f(x)=2x^3-3x^2-432x

extreme points

f (x) = 2 x^{3} - 3 x^{2} - 432 x

Maximum (- 8, 2240), Minimum (9, - 2673)

Solution steps

f^{'} (x) = 6 x^{2} - 6 x - 432

Find intervals:

Increasing

: - \infty < x < - 8,

Decreasing

: - 8 < x < 9,

Increasing

: 9 < x < \infty

Plug

x = - 8

into

2 x^{3} - 3 x^{2} - 432 x : 2240

Maximum (- 8, 2240)

Plug

x = 9

into

2 x^{3} - 3 x^{2} - 432 x : - 2673

Minimum (9, - 2673)

Maximum (- 8, 2240), Minimum (9, - 2673)

\frac{x ^{2}}{x ^{2} - 1}

y = - 6 x^{3} + 2 x

f (x) = x^{2} ∣ x ∣ + 3

f (x) = 2 x^{2} + 8 x

\frac{4}{x - 3}

What is the extreme f(x)=2x^3-3x^2-432x ?
The extreme f(x)=2x^3-3x^2-432x is Maximum(-8,2240),Minimum(9,-2673)