What is the inverse of f(x)=(2x+1)/(1-3x) ?

The inverse of f(x)=(2x+1)/(1-3x) is -(1-x)/(2+3x)

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inverse of f(x)=(2x+1)/(1-3x)

inverse

f (x) = \frac{2 x + 1}{1 - 3 x}

- \frac{1 - x}{2 + 3 x}

Solution steps

y = \frac{2 x + 1}{1 - 3 x}

Replace

x

with

y

x = \frac{2 y + 1}{1 - 3 y}

Solve for

y, x = \frac{2 y + 1}{1 - 3 y}

- \frac{1 - x}{2 + 3 x}

f (x) = x^{2} - 5, x \geq 0

f (x) = \frac{x ^{2} + x - 2}{2 x ^{2} - 2}

5 p + 2 q = 4

\frac{x - 6}{x ^{2} - 36}

(48, 100), (42, 125)

What is the inverse of f(x)=(2x+1)/(1-3x) ?
The inverse of f(x)=(2x+1)/(1-3x) is -(1-x)/(2+3x)