What is the perpendicular 8x-3y=25,(5,-5) ?

The perpendicular 8x-3y=25,(5,-5) is y=-3/8 x-25/8

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perpendicular 8x-3y=25,(5,-5)

perpendicular

8 x - 3 y = 25, (5, - 5)

y = - \frac{3}{8} x - \frac{25}{8}

Solution steps

Find the line

y = mx + b

perpendicular to

8 x - 3 y = 25

that passes through

(5, - 5)

Find the slope of

8 x - 3 y = 25 : m = \frac{8}{3}

Compute the slope of the perpendicular line:

m_{p} = - \frac{3}{8}

Find the line with slope m=

- \frac{3}{8}

and passing through

(5, - 5) : y = - \frac{3}{8} x - \frac{25}{8}

y = - \frac{3}{8} x - \frac{25}{8}

f (x) = 3 + 7 x

3 x - 7 y = 21

f (x) = - 3 x^{2} + 3 x - 2

f (x) = 10 - \frac{1}{5 x}

g (x) = x - 6

What is the perpendicular 8x-3y=25,(5,-5) ?
The perpendicular 8x-3y=25,(5,-5) is y=-3/8 x-25/8