What is the perpendicular y= 1/5 x+5,(6,-4) ?

The perpendicular y= 1/5 x+5,(6,-4) is y=-5x+26

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perpendicular y= 1/5 x+5,(6,-4)

perpendicular

y = \frac{1}{5} x + 5, (6, - 4)

y = - 5 x + 26

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{1}{5} x + 5

that passes through

(6, - 4)

Find the slope of

y = \frac{1}{5} x + 5 : m = \frac{1}{5}

Compute the slope of the perpendicular line:

m_{p} = - 5

Find the line with slope m=

- 5

and passing through

(6, - 4) : y = - 5 x + 26

y = - 5 x + 26

f (x) = - x + 5

f (x) = x^{3} + 18 x^{2} + 11 x - 16

y - 1 = 9 (x - 1)

f (x) = 5 ln (x)

lo g_{3} (x - 4)

What is the perpendicular y= 1/5 x+5,(6,-4) ?
The perpendicular y= 1/5 x+5,(6,-4) is y=-5x+26