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Popular >

range of y=2x^2+20x+53

Solution

range

y = 2 x^{2} + 20 x + 53

Solution

f (x) \geq 3

+1

Interval Notation

[3, \infty)

Solution steps

Vertex of

2 x^{2} + 20 x + 53 :

Minimum

(- 5, 3)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 2,

Vertex

(x_{v}, y_{v}) = (- 5, 3)

f (x) \geq 3

Popular Examples

domain of f(x)=-2x+5 domain

f (x) = - 2 x + 5

domain of x|x|domain

x ∣ x ∣

domain of sqrt(x+8)-9 domain

x + 8 - 9

inverse of f(x)=5+6x inverse

f (x) = 5 + 6 x

inverse of f(x)= 1/5 x-3 inverse

f (x) = \frac{1}{5} x - 3

Frequently Asked Questions (FAQ)

What is the range of y=2x^2+20x+53 ?
The range of y=2x^2+20x+53 is f(x)>= 3