What is the critical f(x)=3x^2-9x ?

The critical f(x)=3x^2-9x is x= 3/2

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critical f(x)=3x^2-9x

critical points

f (x) = 3 x^{2} - 9 x

x = \frac{3}{2}

Solution steps

3 x^{2} - 9 x

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{3}{2}

Identify critical points not in

f (x)

domain

Domain of

3 x^{2} - 9 x : - \infty < x < \infty

All critical points are in domain

x = \frac{3}{2}

\frac{1}{x ^{2}}

x + y = 2

m = \frac{2}{3} (3 - 1)

f (x) = 3 - (3 - x^{2})

\frac{2 x + 3}{x - 4}