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Popular >

shift-7sin(2x+pi/2)

Solution

shift

- 7 sin (2 x + \frac{π}{2})

Solution

Phase : - \frac{π}{4}, Vertical : 0

Solution steps

f (x) = - 7 sin (2 x + \frac{π}{2})

g (B x - C) = sin (2 x + \frac{π}{2}), B = 2, C = - \frac{π}{2}, D = 0

Therefore, the phase shift

\frac{C}{B}

is

\frac{- \frac{π}{2}}{2}

- \frac{π}{4}

The vertical shift

D

is

0

0

Popular Examples

symmetry y=x^2+4x+3 symmetry

y = x^{2} + 4 x + 3

range of (x^2-9)/(x^2+2x-3)range

\frac{x ^{2} - 9}{x ^{2} + 2 x - 3}

inverse of f(x)= 2/(5x+8)inverse

f (x) = \frac{2}{5 x + 8}

inverse of f(x)=f(1)=6 inverse

f (x) = f (1) = 6

intercepts of (x^2-x-12)/(2x-8)intercepts

\frac{x ^{2} - x - 12}{2 x - 8}

Frequently Asked Questions (FAQ)

What is the shift-7sin(2x+pi/2) ?
The shift-7sin(2x+pi/2) is Phase:-pi/4 , Vertical:0