What is the inverse of f(x)= 2/3 (x-1)^2 ?

The inverse of f(x)= 2/3 (x-1)^2 is sqrt((3x)/2)+1,-sqrt((3x)/2)+1

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inverse of f(x)= 2/3 (x-1)^2

inverse

f (x) = \frac{2}{3} (x - 1)^{2}

\frac{3 x}{2} + 1, - \frac{3 x}{2} + 1

Solution steps

y = \frac{2}{3} (x - 1)^{2}

Replace

x

with

y

x = \frac{2}{3} (y - 1)^{2}

Solve for

y, x = \frac{2}{3} (y - 1)^{2}

\frac{3 x}{2} + 1, - \frac{3 x}{2} + 1

12 x^{3}

f (x) = x ln (x)

\frac{x}{4 x - 3}

f (x) = (x + 5)^{2}

f (x) = 8 x + 4

What is the inverse of f(x)= 2/3 (x-1)^2 ?
The inverse of f(x)= 2/3 (x-1)^2 is sqrt((3x)/2)+1,-sqrt((3x)/2)+1