What is the domain of f(x)=arctan(((x-1))/(x+1)) ?

The domain of f(x)=arctan(((x-1))/(x+1)) is x -1

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domain of f(x)=arctan(((x-1))/(x+1))

domain

f (x) = arctan (\frac{( x - 1 )}{x + 1})

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

\frac{9 x - 4}{5 - x}

2 x - 3 y = 3

f (x) = (x - 2) (x + 1)

f (x) = 20 x - 2 x^{2}

y + 2 x = 5

What is the domain of f(x)=arctan(((x-1))/(x+1)) ?
The domain of f(x)=arctan(((x-1))/(x+1)) is x<-1\lor x>-1