What is the domain of f(x)= x/(\sqrt[4]{1-x^2)} ?

The domain of f(x)= x/(\sqrt[4]{1-x^2)} is -1<x<1

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domain of f(x)= x/(\sqrt[4]{1-x^2)}

domain

- 1 < x < 1

Interval Notation

(- 1, 1)

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 1

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

- 1 < x < 1

y = \frac{1}{4} - \frac{3}{2} x

f (x) = {- 4, x > 6}

f (x) = 8 x^{3} - 6 x + 6

y = 8^{x + 2} - 13

f (x) = (x - 2)^{2}

What is the domain of f(x)= x/(\sqrt[4]{1-x^2)} ?
The domain of f(x)= x/(\sqrt[4]{1-x^2)} is -1<x<1