What is the range of f(x)= 7/((x-2)) ?

The range of f(x)= 7/((x-2)) is f(x) 0

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range of f(x)= 7/((x-2))

range

f (x) = \frac{7}{( x - 2 )}

f (x) < 0 or f (x) > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{7}{x - 2}

Inverse of

\frac{7}{x - 2} : \frac{7}{x} + 2

\frac{7}{x} + 2

Find the domain of each inverse function

Domain of

\frac{7}{x} + 2 : x < 0 or x > 0

Combine the intervals

f (x) < 0 or f (x) > 0

g (x) = 4 x - 3

f (x) = 7 + x

\frac{x}{( x - 8 ) ( x + 8 )}

y = 6^{x}

f (x) = \frac{x ^{3} + x}{x ^{2} - 6 x + 5}

What is the range of f(x)= 7/((x-2)) ?
The range of f(x)= 7/((x-2)) is f(x)<0\lor f(x)>0