What is the inverse of f(x)=((x+1))/((x-2)) ?

The inverse of f(x)=((x+1))/((x-2)) is (1+2x)/(x-1)

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inverse of f(x)=((x+1))/((x-2))

inverse

f (x) = \frac{( x + 1 )}{( x - 2 )}

\frac{1 + 2 x}{x - 1}

Solution steps

y = \frac{x + 1}{x - 2}

Replace

x

with

y

x = \frac{y + 1}{y - 2}

Solve for

y, x = \frac{y + 1}{y - 2}

\frac{1 + 2 x}{x - 1}

f (x) = 15 - x

x^{3} - 64

f (x) = lo g_{3} (- x - 4) - 1

f (x) = \frac{x ^{2}}{x ^{2} - 25}

y = \frac{- 3}{4} x + 2

What is the inverse of f(x)=((x+1))/((x-2)) ?
The inverse of f(x)=((x+1))/((x-2)) is (1+2x)/(x-1)