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Popular >

extreme f(x)=(x^2-8x)

Solution

extreme points

f (x) = (x^{2} - 8 x)

Solution

Minimum (4, - 16)

Solution steps

f^{'} (x) = 2 x - 8

Find intervals:

Decreasing

: - \infty < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 4

into

x^{2} - 8 x : - 16

Minimum (4, - 16)

Popular Examples

line m=-7/6 ,(-6,-2)line

m = - \frac{7}{6}, (- 6, - 2)

extreme f(x)=-x^4+x^3+2x^2 extreme points

f (x) = - x^{4} + x^{3} + 2 x^{2}

inverse of f(x)=(x+1)/(2x+3)inverse

f (x) = \frac{x + 1}{2 x + 3}

domain of f(x)= 1/x-4 domain

f (x) = \frac{1}{x} - 4

range of x^2+4x+4 range

x^{2} + 4 x + 4

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x^2-8x) ?
The extreme f(x)=(x^2-8x) is Minimum(4,-16)