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Popular >

midpoint (0,-10),(1,-3)

Solution

midpoint

(0, - 10), (1, - 3)

Solution

(\frac{1}{2}, - \frac{13}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (0, - 10), (x_{2}, y_{2}) = (1, - 3)

= (\frac{1 + 0}{2}, \frac{- 3 - 10}{2})

Refine

= (\frac{1}{2}, - \frac{13}{2})

Popular Examples

symmetry x^4-x^2 symmetry

x^{4} - x^{2}

domain of f(x)=sqrt(24-4x)domain

f (x) = 24 - 4 x

intercepts of 1/(x^2+2)intercepts

\frac{1}{x ^{2} + 2}

domain of f(x)=9-4x^2 domain

f (x) = 9 - 4 x^{2}

range of f(x)=-2x^2-5 range

f (x) = - 2 x^{2} - 5

Frequently Asked Questions (FAQ)

What is the midpoint (0,-10),(1,-3) ?
The midpoint (0,-10),(1,-3) is (1/2 ,-13/2)