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midpoint
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domain of (x^2-3x)/(2x^2+2x-12)domain midpoint (8,10),(-2,-14)midpoint parity f(x)=x^3-5x+7parity symmetry (x-4)^2symmetry inverse of f(x)= 1/(4x)+3inverse
Frequently Asked Questions (FAQ)
What is the midpoint (sqrt(2),-sqrt(7)),(-4sqrt(2),-5sqrt(7)) ?
The midpoint (sqrt(2),-sqrt(7)),(-4sqrt(2),-5sqrt(7)) is (-3/(sqrt(2)),-3sqrt(7))