What is the extreme f(x)=(x-1)^2(x+2) ?

The extreme f(x)=(x-1)^2(x+2) is Maximum(-1,4),Minimum(1,0)

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extreme f(x)=(x-1)^2(x+2)

extreme points

f (x) = (x - 1)^{2} (x + 2)

Maximum (- 1, 4), Minimum (1, 0)

Solution steps

f^{'} (x) = 3 (x - 1) (x + 1)

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

(x - 1)^{2} (x + 2) : 4

Maximum (- 1, 4)

Plug

x = 1

into

(x - 1)^{2} (x + 2) : 0

Minimum (1, 0)

Maximum (- 1, 4), Minimum (1, 0)

y = 4 x - 2, (4, - 11)

m = - 3, (1, 6)

f (- 1 \frac{2}{3}) = \frac{5}{x - 8}

f (x) = - \frac{2}{x - 1} - 2

(1, - 3), (- 7, - 3)

What is the extreme f(x)=(x-1)^2(x+2) ?
The extreme f(x)=(x-1)^2(x+2) is Maximum(-1,4),Minimum(1,0)