What is the domain of f(x)=sqrt(x^2-9x) ?

The domain of f(x)=sqrt(x^2-9x) is x = 9

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domain of f(x)=sqrt(x^2-9x)

domain

f (x) = x^{2} - 9 x

x \leq 0 or x \geq 9

Interval Notation

(- \infty, 0] \cup [9, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 9

The function domain

x \leq 0 or x \geq 9

- 2 \cdot 3^{x}

y = \frac{x - 5}{( x - 1 ) ( x - 4 )}

\frac{1}{x + 1}

x

f (x) = 2 x^{2} + 4 x - 8

What is the domain of f(x)=sqrt(x^2-9x) ?
The domain of f(x)=sqrt(x^2-9x) is x<= 0\lor x>= 9