What is the critical 18cos(x)+9sin^2(x) ?

The critical 18cos(x)+9sin^2(x) is x=2pin,x=pi+2pin

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critical 18cos(x)+9sin^2(x)

critical points

18 cos (x) + 9 sin^{2} (x)

x = 2 πn, x = π + 2 πn

Solution steps

18 cos (x) + 9 sin^{2} (x)

Find where

f^{'} (x)

is equal to zero or undefined

x = 2 πn, x = π + 2 πn

Identify critical points not in

f (x)

domain

Domain of

18 cos (x) + 9 sin^{2} (x) : - \infty < x < \infty

All critical points are in domain

x = 2 πn, x = π + 2 πn

f (x) = tan (2 (x - \frac{π}{3}))

f (x) = 5 + 2 e^{x}

\frac{3 a}{2 a + 25}

y = - 2 x^{2} - x + 6

f (x) = \frac{5 x ^{3} - 11}{9}

What is the critical 18cos(x)+9sin^2(x) ?
The critical 18cos(x)+9sin^2(x) is x=2pin,x=pi+2pin