What is the inverse of f(x)= 1/(2x-1)+3 ?

The inverse of f(x)= 1/(2x-1)+3 is (x-2)/(2(-3+x))

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inverse of f(x)= 1/(2x-1)+3

inverse

f (x) = \frac{1}{2 x - 1} + 3

\frac{x - 2}{2 ( - 3 + x )}

Solution steps

y = \frac{1}{2 x - 1} + 3

Replace

x

with

y

x = \frac{1}{2 y - 1} + 3

Solve for

y, x = \frac{1}{2 y - 1} + 3

\frac{x - 2}{2 ( - 3 + x )}

\frac{( x + 9 ) ( x - 9 )}{x ^{2} + 81}

(2, - 1), (4, - 1)

f (x) = lo g_{a} (x)

f (x) = \frac{x + 4}{x - 3}

(0, - 4), (2, 4)

What is the inverse of f(x)= 1/(2x-1)+3 ?
The inverse of f(x)= 1/(2x-1)+3 is (x-2)/(2(-3+x))