What is the inverse of x/(x^2+3) ?

The inverse of x/(x^2+3) is (1+sqrt(1-12x^2))/(2x),(1-sqrt(1-12x^2))/(2x)

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inverse of x/(x^2+3)

inverse

\frac{x}{x ^{2} + 3}

\frac{1 + 1 - 12 x ^{2}}{2 x}, \frac{1 - 1 - 12 x ^{2}}{2 x}

Solution steps

y = \frac{x}{x ^{2} + 3}

Replace

x

with

y

x = \frac{y}{y ^{2} + 3}

Solve for

y, x = \frac{y}{y ^{2} + 3}

\frac{1 + 1 - 12 x ^{2}}{2 x}, \frac{1 - 1 - 12 x ^{2}}{2 x}

f (x) = 7 x^{4}

f (x) = 2 x^{2} + 1

y = - x^{2} + 1

f (x) = - x + 3

f (x) = \frac{1}{x}

What is the inverse of x/(x^2+3) ?
The inverse of x/(x^2+3) is (1+sqrt(1-12x^2))/(2x),(1-sqrt(1-12x^2))/(2x)