What is the domain of f(x)=sqrt(16-x^2)*sqrt(x+1) ?

The domain of f(x)=sqrt(16-x^2)*sqrt(x+1) is -1<= x<= 4

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domain of f(x)=sqrt(16-x^2)*sqrt(x+1)

domain

f (x) = 16 - x^{2} \cdot x + 1

- 1 \leq x \leq 4

Interval Notation

[- 1, 4]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 4

The function domain

- 1 \leq x \leq 4

3 - 4 x

(7.6) (1.1)

\frac{2 x ^{2} - 7 x - 15}{x ^{2} - 3 x - 10}

- x^{2} + 3

y = 2 x + 5

What is the domain of f(x)=sqrt(16-x^2)*sqrt(x+1) ?
The domain of f(x)=sqrt(16-x^2)*sqrt(x+1) is -1<= x<= 4