What is the critical 2/((x+2)(x-3)) ?

The critical 2/((x+2)(x-3)) is x= 1/2

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critical 2/((x+2)(x-3))

critical points

\frac{2}{( x + 2 ) ( x - 3 )}

x = \frac{1}{2}

Solution steps

\frac{2}{( x + 2 ) ( x - 3 )}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{2}, x = - 2, x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{2}{( x + 2 ) ( x - 3 )} : x < - 2 or - 2 < x < 3 or x > 3

\frac{2}{( x + 2 ) ( x - 3 )}

is not defined at

x = - 2, x = 3

, therefore:

x = \frac{1}{2}

(x - 2)^{2} - 1

y = - x^{3}

3 x^{4} + 4 x^{3}

f (x) = \frac{8}{( 2 x - 5 ) ^{3}}

\frac{1}{x + 5} + 2