What is the slope ofintercept y-1=-3(x-4) ?

The slope ofintercept y-1=-3(x-4) is y=-3x+13

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slope ofintercept y-1=-3(x-4)

slope intercept

y - 1 = - 3 (x - 4)

y = - 3 x + 13

Solution steps

y - 1 = - 3 (x - 4)

Convert to slope intercept form:

y = - 3 x + 13

For a line in the form of

y = mx + b

, the slope is

m

and

y

intercept is

b

y = - 3 x + 13

f (x) = 5 x^{\frac{2}{3}} + 10

y = 7 x + 6

y - 6 = - 5 (x - 3)

y = - \frac{1}{5} x - 3

f (x) = - 16 - x^{2}

What is the slope ofintercept y-1=-3(x-4) ?
The slope ofintercept y-1=-3(x-4) is y=-3x+13