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Popular >

range of (x+1)^2-9

Solution

range

(x + 1)^{2} - 9

Solution

f (x) \geq - 9

+1

Interval Notation

[- 9, \infty)

Solution steps

Vertex of

(x + 1)^{2} - 9 :

Minimum

(- 1, - 9)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (- 1, - 9)

f (x) \geq - 9

Popular Examples

perpendicular x+y=8 perpendicular

x + y = 8

inverse of f(x)=sqrt(x^2+4)inverse

f (x) = x^{2} + 4

domain of log_{4}((x-3)/x)domain

lo g_{4} (\frac{x - 3}{x})

domain of log_{4}(3^x)domain

lo g_{4} (3^{x})

slope ofintercept 4x+y=-2 slope intercept

4 x + y = - 2

Frequently Asked Questions (FAQ)

What is the range of (x+1)^2-9 ?
The range of (x+1)^2-9 is f(x)>=-9