What is the critical (0.22x)/(x^2+4) ?

The critical (0.22x)/(x^2+4) is x=-2,x=2

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critical (0.22x)/(x^2+4)

critical points

\frac{0.22 x}{x ^{2} + 4}

x = - 2, x = 2

Solution steps

\frac{0.22 x}{x ^{2} + 4}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{0.22 x}{x ^{2} + 4} : - \infty < x < \infty

All critical points are in domain

x = - 2, x = 2

5 y = 2 x - 4, (0, 7)

\frac{- x + 3}{x ^{2} - 1}

x^{2} - x - 6

(- 2, - 4), (4, 4)

6 x - 3 y = 9