What is the domain of 1/(3x-12)sqrt(2x+6) ?

The domain of 1/(3x-12)sqrt(2x+6) is -3 4

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domain of 1/(3x-12)sqrt(2x+6)

domain

\frac{1}{3 x - 12} 2 x + 6

- 3 \leq x < 4 or x > 4

Interval Notation

[- 3, 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 3

Find undefined (singularity) points:

x = 4

Combine real regions and undefined points for final function domain

- 3 \leq x < 4 or x > 4

f (x) = \frac{5}{x + 7} - 8

\frac{2 x ^{2} - 2}{x ^{2} - 4 x + 3}

y = - \frac{2}{5} x + 2

f (x) = t + 5

f (x) = e^{- x^{2}}

What is the domain of 1/(3x-12)sqrt(2x+6) ?
The domain of 1/(3x-12)sqrt(2x+6) is -3<= x<4\lor x>4