What is the domain of f(x)=(3x)/(x^3+4x^2-x-4) ?

The domain of f(x)=(3x)/(x^3+4x^2-x-4) is x 1

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domain of f(x)=(3x)/(x^3+4x^2-x-4)

domain

f (x) = \frac{3 x}{x ^{3} + 4 x ^{2} - x - 4}

x < - 4 or - 4 < x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 4) \cup (- 4, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 4, x = - 1, x = 1

The function domain

x < - 4 or - 4 < x < - 1 or - 1 < x < 1 or x > 1

f (x) = (x - 3)^{2} + 2

f (x) = - 2 x^{3} - 27 x^{2} - 84 x - 3

f (x) = x^{2} - 6 x + 7

f (x) = 6 x + 2

f (x) = 10 - 4 x

What is the domain of f(x)=(3x)/(x^3+4x^2-x-4) ?
The domain of f(x)=(3x)/(x^3+4x^2-x-4) is x<-4\lor-4<x<-1\lor-1<x<1\lor x>1