What is the domain of sqrt(((x+4)(x+5))/(x-7)) ?

The domain of sqrt(((x+4)(x+5))/(x-7)) is -5 7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of sqrt(((x+4)(x+5))/(x-7))

domain

\frac{( x + 4 ) ( x + 5 )}{x - 7}

- 5 \leq x \leq - 4 or x > 7

Interval Notation

[- 5, - 4] \cup (7, \infty)

Solution steps

Find non-negative values for radicals:

- 5 \leq x \leq - 4 or x > 7

Find undefined (singularity) points:

x = 7

Combine real regions and undefined points for final function domain

- 5 \leq x \leq - 4 or x > 7

y = \frac{1}{x + 2}

4 x^{3} - 5

\frac{x + 3}{x - 2}

\frac{2 x}{x ^{2} + 1}

\frac{1}{x - 4} + 2

What is the domain of sqrt(((x+4)(x+5))/(x-7)) ?
The domain of sqrt(((x+4)(x+5))/(x-7)) is -5<= x<=-4\lor x>7