What is the monotone f(x)= 1/(6x+4) ?

The monotone f(x)= 1/(6x+4) is Decreasing:-infinity <x<-2/3 ,Decreasing:-2/3 <x<infinity

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monotone f(x)= 1/(6x+4)

monotone intervals

f (x) = \frac{1}{6 x + 4}

Decreasing : - \infty < x < - \frac{2}{3}, Decreasing : - \frac{2}{3} < x < \infty

Solution steps

f^{'} (x) = - \frac{3}{2 ( 3 x + 2 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < - \frac{2}{3},

Decreasing

: - \frac{2}{3} < x < \infty

Decreasing : - \infty < x < - \frac{2}{3}, Decreasing : - \frac{2}{3} < x < \infty

(1, - 1), (9, 4)

3 x^{2} + 6 x - 1

12 x + 3 y = 7

f (x) = \frac{3 x ^{2} + x}{x ^{2} + 3 x + 2}

5 x + 2 y = 10

What is the monotone f(x)= 1/(6x+4) ?
The monotone f(x)= 1/(6x+4) is Decreasing:-infinity <x<-2/3 ,Decreasing:-2/3 <x<infinity