What is the domain of y(θ)=sin(θ+pi/2) ?

The domain of y(θ)=sin(θ+pi/2) is -infinity <θ<infinity

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domain of y(θ)=sin(θ+pi/2)

domain

y (θ) = sin (θ + \frac{π}{2})

- \infty < θ < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < θ < \infty

\frac{9 - x ^{2}}{x + 1}

f (x) = - \frac{( 1 )}{2 7 - x}

x + 8 - x

x^{2} - 1

f (x) = \frac{x}{x ^{2} - 16}

What is the domain of y(θ)=sin(θ+pi/2) ?
The domain of y(θ)=sin(θ+pi/2) is -infinity <θ<infinity