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Popular >

extreme 9/(x^2-1)

Solution

extreme points

\frac{9}{x ^{2} - 1}

Solution

Maximum (0, - 9)

Solution steps

f^{'} (x) = - \frac{18 x}{( x ^{2} - 1 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 0,

Decreasing

: 0 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = 0

into

\frac{9}{x ^{2} - 1} : - 9

Maximum (0, - 9)

Popular Examples

inverse of f(x)=(-x-8)/7 inverse

f (x) = \frac{- x - 8}{7}

critical f(x)=(x+6)/(x+1)critical points

f (x) = \frac{x + 6}{x + 1}

inverse of f(x)=log_{4}(x+3)inverse

f (x) = lo g_{4} (x + 3)

asymptotes of f(x)=(-3x^2+2)/(x-1)asymptotes

f (x) = \frac{- 3 x ^{2} + 2}{x - 1}

parity 1/(x^n)parity

\frac{1}{x ^{n}}

Frequently Asked Questions (FAQ)

What is the extreme 9/(x^2-1) ?
The extreme 9/(x^2-1) is Maximum(0,-9)