What is the monotone f(x)=-1/2 x^2+7x-3 ?

The monotone f(x)=-1/2 x^2+7x-3 is Increasing:-infinity <x<7,Decreasing:7<x<infinity

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monotone f(x)=-1/2 x^2+7x-3

monotone intervals

f (x) = - \frac{1}{2} x^{2} + 7 x - 3

Increasing : - \infty < x < 7, Decreasing : 7 < x < \infty

Solution steps

f^{'} (x) = - x + 7

Find intervals:

Increasing

: - \infty < x < 7,

Decreasing

: 7 < x < \infty

Increasing : - \infty < x < 7, Decreasing : 7 < x < \infty

f (x) = x^{2} - 12 x + 2

\frac{2}{1 - x}

2 x - 5 y = 9

f (x) = - \frac{1}{2} x^{2} + 2 x + 3

f (x) = x^{2} + 4 x + 2

What is the monotone f(x)=-1/2 x^2+7x-3 ?
The monotone f(x)=-1/2 x^2+7x-3 is Increasing:-infinity <x<7,Decreasing:7<x<infinity