What is the inverse of ((x^2-5))/(7x^2) ?

The inverse of ((x^2-5))/(7x^2) is sqrt(-5/(7x-1)),-sqrt(-5/(7x-1))

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inverse of ((x^2-5))/(7x^2)

inverse

\frac{( x ^{2} - 5 )}{7 x ^{2}}

- \frac{5}{7 x - 1}, - - \frac{5}{7 x - 1}

Solution steps

y = \frac{x ^{2} - 5}{7 x ^{2}}

Replace

x

with

y

x = \frac{y ^{2} - 5}{7 y ^{2}}

Solve for

y, x = \frac{y ^{2} - 5}{7 y ^{2}}

- \frac{5}{7 x - 1}, - - \frac{5}{7 x - 1}

7 x - y = - 4

y = 2 x - 10

7 + 3 x

x - \frac{1}{x}

f (5 x) = 4 x^{(2)} + 4 x - 4

What is the inverse of ((x^2-5))/(7x^2) ?
The inverse of ((x^2-5))/(7x^2) is sqrt(-5/(7x-1)),-sqrt(-5/(7x-1))