What is the inverse of f(x)=(x^7+4)^{1/5}-2 ?

The inverse of f(x)=(x^7+4)^{1/5}-2 is \sqrt[7]{x^5+10x^4+40x^3+80x^2+80x+28}

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inverse of f(x)=(x^7+4)^{1/5}-2

inverse

f (x) = (x^{7} + 4)^{\frac{1}{5}} - 2

Solution steps

y = (x^{7} + 4)^{\frac{1}{5}} - 2

Replace

x

with

y

x = (y^{7} + 4)^{\frac{1}{5}} - 2

Solve for

y, x = (y^{7} + 4)^{\frac{1}{5}} - 2

f (x) = \frac{x}{x ( x + 3 )}

f (x) = - \frac{1}{5} sin (\frac{x}{3})

\frac{x}{x - 2}

f (x) = 3 - 4 x + 2

7 x + 2

What is the inverse of f(x)=(x^7+4)^{1/5}-2 ?
The inverse of f(x)=(x^7+4)^{1/5}-2 is \sqrt[7]{x^5+10x^4+40x^3+80x^2+80x+28}