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Popular >

range of f(x)=2x^2+16x+96

Solution

range

f (x) = 2 x^{2} + 16 x + 96

Solution

f (x) \geq 64

+1

Interval Notation

[64, \infty)

Solution steps

Vertex of

2 x^{2} + 16 x + 96 :

Minimum

(- 4, 64)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 2,

Vertex

(x_{v}, y_{v}) = (- 4, 64)

f (x) \geq 64

Popular Examples

inverse of f(x)=0.5x+3 inverse

f (x) = 0.5 x + 3

f (x) = 1 - cos (x)

domain of f(x)= 3/(x+13)domain

f (x) = \frac{3}{x + 13}

asymptotes of f(x)=-5^x asymptotes

f (x) = - 5^{x}

range of f(x)=x^2+4x+6 range

f (x) = x^{2} + 4 x + 6

Frequently Asked Questions (FAQ)

What is the range of f(x)=2x^2+16x+96 ?
The range of f(x)=2x^2+16x+96 is f(x)>= 64