What is the range of f(x)=4+7sqrt(25-x^2) ?

The range of f(x)=4+7sqrt(25-x^2) is 4<= f(x)<= 39

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of f(x)=4+7sqrt(25-x^2)

range

f (x) = 4 + 7 25 - x^{2}

4 \leq f (x) \leq 39

Interval Notation

[4, 39]

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

4 + 7 25 - x^{2} : - 5 \leq x \leq 5

Extreme Points of

4 + 7 25 - x^{2} :

Minimum

(- 5, 4),

Maximum

(0, 39),

Minimum

(5, 4)

Find the range for the interval

- 5 \leq x \leq 5 : 4 \leq f (x) \leq 39

Combine the ranges of all domain intervals to obtain the function range

4 \leq f (x) \leq 39

f (x) = \frac{x}{x ^{2} + 4 x + 3}

f (g (2)), g (x) = 2 x + 1, f (x) = x^{2}

y + 12 = - 3 (x - 4)

f (x) = 2 x - 8

- 2 sin (x + \frac{π}{2})

What is the range of f(x)=4+7sqrt(25-x^2) ?
The range of f(x)=4+7sqrt(25-x^2) is 4<= f(x)<= 39