What is the domain of f(x)= 1/2 (3)^{x+4}-5 ?

The domain of f(x)= 1/2 (3)^{x+4}-5 is -infinity <x<infinity

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domain of f(x)= 1/2 (3)^{x+4}-5

domain

f (x) = \frac{1}{2} (3)^{x + 4} - 5

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = x^{2} (x - 4) (x^{2} + 6)

f (x) = \frac{x ^{2} - 2 x - 3}{x - 2}

f (x) = \frac{6 + x}{1 - 6 x}

f (x) = 2 x - 5

f (x) = 1 - 3 x - x^{2}

What is the domain of f(x)= 1/2 (3)^{x+4}-5 ?
The domain of f(x)= 1/2 (3)^{x+4}-5 is -infinity <x<infinity