What is the critical (x-4)(x/2+1)^3 ?

The critical (x-4)(x/2+1)^3 is x=-2,x\approx-1.99999…,x\approx 2.50000…

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critical (x-4)(x/2+1)^3

critical points

(x - 4) (\frac{x}{2} + 1)^{3}

x = - 2, x \approx - 1.99999 \dots, x \approx 2.50000 \dots

Solution steps

(x - 4) (\frac{x}{2} + 1)^{3}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x \approx - 1.99999 \dots, x \approx 2.50000 \dots

Identify critical points not in

f (x)

domain

Domain of

(x - 4) (\frac{x}{2} + 1)^{3} : - \infty < x < \infty

All critical points are in domain

x = - 2, x \approx - 1.99999 \dots, x \approx 2.50000 \dots

f (x) = \frac{1}{2} x^{3}

m = - 5

1 - cos (x)

f (x) = \frac{2 x + 1}{x - 3}

f (x) = \frac{1}{x ^{2}} - 5

What is the critical (x-4)(x/2+1)^3 ?
The critical (x-4)(x/2+1)^3 is x=-2,x\approx-1.99999…,x\approx 2.50000…