What is the inverse of y=3x^2+x+2 ?

The inverse of y=3x^2+x+2 is (-1+sqrt(12x-23))/6 ,(-1-sqrt(12x-23))/6

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inverse of y=3x^2+x+2

inverse

y = 3 x^{2} + x + 2

\frac{- 1 + 12 x - 23}{6}, \frac{- 1 - 12 x - 23}{6}

Solution steps

y = 3 x^{2} + x + 2

Replace

x

with

y

x = 3 y^{2} + y + 2

Solve for

y, x = 3 y^{2} + y + 2

\frac{- 1 + 12 x - 23}{6}, \frac{- 1 - 12 x - 23}{6}

f (x) = - 2 x e^{- 3 x}

f (x) = 3 x^{2} - 6

f (x) = - \frac{4}{x ^{2} - 3 x + 6}

3 x + 6 y = 5, at

y = 3 - 5 x

What is the inverse of y=3x^2+x+2 ?
The inverse of y=3x^2+x+2 is (-1+sqrt(12x-23))/6 ,(-1-sqrt(12x-23))/6