en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of x^2+6x+8

Solution

range

x^{2} + 6 x + 8

Solution

f (x) \geq - 1

+1

Interval Notation

[- 1, \infty)

Solution steps

Vertex of

x^{2} + 6 x + 8 :

Minimum

(- 3, - 1)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (- 3, - 1)

f (x) \geq - 1

Popular Examples

domain of f(x)=-3x^2+2 domain

f (x) = - 3 x^{2} + 2

inverse of f(x)=(1-x)^3 inverse

f (x) = (1 - x)^{3}

inverse of f(x)=(1-x)/(4x-3)inverse

f (x) = \frac{1 - x}{4 x - 3}

domain of f(x)=1.8x-2.7 domain

f (x) = 1.8 x - 2.7

inverse of y=2^{x-3}+1 inverse

y = 2^{x - 3} + 1

Frequently Asked Questions (FAQ)

What is the range of x^2+6x+8 ?
The range of x^2+6x+8 is f(x)>=-1