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Popular >

range of f(x)=8x^2+9

Solution

range

f (x) = 8 x^{2} + 9

Solution

f (x) \geq 9

+1

Interval Notation

[9, \infty)

Solution steps

Vertex of

8 x^{2} + 9 :

Minimum

(0, 9)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 8,

Vertex

(x_{v}, y_{v}) = (0, 9)

f (x) \geq 9

Popular Examples

domain of f(x)= 9/(x+5)domain

f (x) = \frac{9}{x + 5}

parity f(x)=(x^2)/(x^4+1)parity

f (x) = \frac{x ^{2}}{x ^{4} + 1}

asymptotes of f(x)= 1/(e^x+1)asymptotes

f (x) = \frac{1}{e ^{x} + 1}

domain of f(x)=(x-1)^2-2 domain

f (x) = (x - 1)^{2} - 2

domain of 1/(sqrt(2-x))domain

\frac{1}{2 - x}

Frequently Asked Questions (FAQ)

What is the range of f(x)=8x^2+9 ?
The range of f(x)=8x^2+9 is f(x)>= 9