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Popular >

distance (2,-3),(0,0)

Solution

distance

(2, - 3), (0, 0)

Solution

13

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(2, - 3)

and

(0, 0)

is

= (0 - 2)^{2} + (0 - (- 3))^{2}

Simplify

= 13

Popular Examples

critical f(x)=(9-x^2)^{3/5}critical points

f (x) = (9 - x^{2})^{\frac{3}{5}}

domain of x/(8x+9)domain

\frac{x}{8 x + 9}

domain of f(x)=tan(pi/(13)x)domain

f (x) = tan (\frac{π}{13} x)

inverse of (3-x)^{1/2}inverse

(3 - x)^{\frac{1}{2}}

asymptotes of f(x)=(x^2+7x+12)/(-3x-9)asymptotes

f (x) = \frac{x ^{2} + 7 x + 12}{- 3 x - 9}

Frequently Asked Questions (FAQ)

What is the distance (2,-3),(0,0) ?
The distance (2,-3),(0,0) is square root of 13